(2x^2+3)(20x^2-11x-4)=0

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Solution for (2x^2+3)(20x^2-11x-4)=0 equation: 


Simplifying
(2x2 + 3)(20x2 + -11x + -4) = 0

Reorder the terms:
(3 + 2x2)(20x2 + -11x + -4) = 0

Reorder the terms:
(3 + 2x2)(-4 + -11x + 20x2) = 0

Multiply (3 + 2x2) * (-4 + -11x + 20x2)
(3(-4 + -11x + 20x2) + 2x2 * (-4 + -11x + 20x2)) = 0
((-4 * 3 + -11x * 3 + 20x2 * 3) + 2x2 * (-4 + -11x + 20x2)) = 0
((-12 + -33x + 60x2) + 2x2 * (-4 + -11x + 20x2)) = 0
(-12 + -33x + 60x2 + (-4 * 2x2 + -11x * 2x2 + 20x2 * 2x2)) = 0
(-12 + -33x + 60x2 + (-8x2 + -22x3 + 40x4)) = 0

Combine like terms: 60x2 + -8x2 = 52x2
(-12 + -33x + 52x2 + -22x3 + 40x4) = 0

Solving
-12 + -33x + 52x2 + -22x3 + 40x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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